Did Richards Really Do Away with Einstein?

Posted 6 April 2005 by

↗ The current version of this post is on the live site: https://pandasthumb.org/archives/2005/04/did-richards-re.html

As Reed Cartwright noted in a short, brilliantly titled essay yesterday, Discovery Institute Senior Fellow Jay Richards thinks he has found a flaw in the theory of relativity.  The theory of relativity is one of the most successful scientific theories ever, and it has been verified time and again with remarkable precision.  This month’s issue of Discover Magazine, for example, notes that a clock runs measurably faster at a high altitude than at sea level.  A nonscientist criticizing relativity is about like a lawyer criticizing evolution; both are in over their heads.

My own knowledge of relativity, while evidently more profound than Mr. Richards’s, is still not up to par, so I contacted my colleague Victor Stenger, author of Has Science Found God? and asked him to comment on Mr. Richards’s essay. Here is the bulk of his reply, beginning with a quotation from Mr. Richards’s essay.


My vague understanding is that time slows down as you go faster.  When travelling at the speed of light, [sic] time stops.  If you actually could travel at the speed of light, you would — in your own frame of reference — arrive at your destination instantaneously, no matter how long it took in the frame of reference of your home planet.

 

This is not quite right. The moving clock slows only for an observer in another reference frame. It does not slow down in its own reference frame (my italics).

So, for the hypothetical photon released just after the big bang, the “time since the big bang” is basically 0.

Only in the photon’s rest frame, and a photon is never at rest.

However, I think I see the point he is trying to make. It is true that an observer moving at a speed near the speed of light relative to Earth would in fact measure a very small time since the big bang.

Just picking a number, let

v=0.999 999 999 999 999 999 999 999 999 999 999 998c,

where c is the speed of light. The Lorentz factor gamma = 1/sqrt[1 - (v/c)2] can be well approximated for v near c by 1/sqrt[2(1-(v/c))].

So here,

v/c = 000 000 000 000 000 000 000 000 000 000 000 002 = 2 x 10-36, and

gamma=1/sqrt(4 x 10-36) = 5 x 1017.

A clock moving at this speed would measure the lifetime of the universe to be

(13.7 x 109 year)/(5 x 1017) = 2.74 x 10-8 year = 0.86 second.

But that’s the whole point of what Einstein said. There is no absolute time. In our reference frame, the universe is 13.7 billion years old.

Mr. Richards is dead wrong when he suggests that thousands of physicists have missed this point. He should learn some physics before he criticizes physicists.


I would add that relativity is conceptually difficult and counterintuitive.  It is impossible to understand without knowing the mathematics, and the results often contradict ‘common sense.’  Mr. Richards, who admits to only a ‘vague understanding,’ is simply wrong in saying that the age of the universe is the same everywhere.  It is not even the same at the top of Mount Everest as at the shore of the Dead Sea; because clocks run faster on Mount Everest, the universe is older there than on the Dead Sea.

Mr. Richards writes of a subject he does not understand or perhaps chooses not to understand.  His essay is of a piece with pronouncements on evolution by Discovery Institute Fellows.

References and notes.

The essay by Mr. Richards may be found at http://www.idthefuture.com/index.php?p=179&more=1&c=1&tb=1&p….

Bob Berman, ‘A Twisted Anniversary,’ Discover, May, 2005, p. 30.

Victor J. Stenger is Professor Emeritus of Physics and Astronomy at the University of Hawaii, and Adjunct Professor of Philosophy at the University of Colorado.  He is author of five published books including Has Science Found God? (Prometheus, 2003), with two more on the way.  http://www.colorado.edu/philosophy/vstenger….

117 Comments

phaedrus · 6 April 2005

I'm sorry if this is a stupid question, but I thought that clocks would move slower on Mt. Everest than at sea level because points farther from the center of the earth travel with greater velocity than points closer. What am I missing? Thanks.

Koly · 6 April 2005

I'm sorry if this is a stupid question, but I thought that clocks would move slower on Mt. Everest than at sea level because points farther from the center of the earth travel with greater velocity than points closer. What am I missing? Thanks.

— phaedrus
You are missing the dilatation caused by the curvature of space-time, i.e. gravitation. Gravitation is weaker on Mt.Everest compared to the sea level.

Matt Young · 6 April 2005

I am very sorry, but the first quotation I sent to Victor Stenger is not by Mr. Richards but from an e-mail by Nicholas Matzke. I somehow conflated Mr. Matzke's e-mail, which contained quotations from Mr. Richards's article, with the article itself. Here is what Mr. Richards actually wrote:

If Big Bang cosmology is broadly true, then right now, everywhere in the universe, it's the same time since the big bang. (There are complexities having to do with the inhomogeneity of the universe here, but let that pass for now.) It's not like it's 13.7 billion years old around here, but only 2 billion years old in some other galaxy. Of course we can't look and see what time it is in the Andromeda galaxy, since it's a couple of million light years away. But that's simply a limit on what we can observe directly. It's still at least roughly the same cosmic time there. So Einstein didn't do away with a universal time, even if he and his interpreters often say that he did.

Mr. Richards did not "admit" to a "vague understanding," and I apologize for writing that he did. The error is entirely mine.

Matt Young · 6 April 2005

You are missing the dilatation caused by the curvature of space-time, i.e. gravitation. Gravitation is weaker on Mt.Everest compared to the sea level.

The point is that the clocks run at different rates in the 2 locations, so the age of the universe (or anything else) is different in the 2 locations. There is no absolute time. No honest question is stupid.

Mark Perakh · 6 April 2005

Although unfortunately Matt Young has inadvertently misled Vic Stenger regarding the quotation from Richards, this in no way makes Richards's "rebuttal" of Einstein anywhere close to being correct. Stenger's explanation in itself is correct, even if not directly addressing Richards's error. As to what Richards has actually written, is just gobbledygook making no sense whatsoever. It hardly can be replied to in a meaningful manner because it is so far from anything scientifically reasonable that there is simply no common ground for a meaningful discussion of that matter between qualified physicists and Richards.

Regarding the time intervals becoming zero in a frame of reference attached to photons (this notion was suggested by Schroeder) such a notion is meaningless because photons, unlike any entities possessing rest mass, cannot be attached to any frame of reference. If they were, they would have zero speed in such a frame, but it is imposssible because all photons always move with the same speed (in vacuum) in all frames of reference (the speed of light). This notion is in fact the seminal concept of special relativity - all the rest of that theory is derived from it.
PS. I've taught all parts of physics, both on undergraduate and graduate levels, for more than half a century.

Matt Young · 6 April 2005

In reply to Professor Perakh: In fact I sent Professor Stenger the correct paragraph by Mr. Richards, along with the paragraph by Mr. Matzke. I cut out that paragraph when I prepared the essay for PT. Professor Stenger's response seems to me to be still pertinent inasmuch as he shows that there is no absolute time. My own comments are also pertinent, except that I should not have accused Mr. Richards of admitting a weak knowledge of relativity; he did not admit that.

Koly · 6 April 2005

I have to admit, Mr.Richardson's "refutation" has boggled my mind. This caused a serious headache until I have come to an inevitable conclusion: we were all wrong and Richardson is right. He really does away with Einstein with a big, so far unmatched, fashion. Read his article carefully and you'll see that the basis of the argument is this:

Right now, my wife is doing something at home. She's doing it right now even though I don't know what it is she's doing.

So he's not at home and he knows that his wife is doing something (and he doesn't seem to like it), though he doesn't know exactly the situation. How does he know it? The only way is numerous past experiences. These are real scientific data! You have to admit that this is a completely different angle of view, which clearly proves that time is indeed absolute. How many of us share similar experiences? I dare to say that there is some huge amount of data waiting out there to be collected from our wives and girlfriends! [wink]

Absolute Time · 6 April 2005

If a clock is moving faster at the top of Mt. Everest than at the bottom, then wouldn't the top eventually be (a) day(s) ahead of the bottom? Which, of course, means that the top would count more sunrises and sunsets and the sun would pass overhead more times. But, how can this be when they are affixed to the same point on the Earth?

Colin · 6 April 2005

While the resident cognoscenti are fielding questions, would you mind clearing something up for me? I understand that the usual figure for the speed of light is its speed in a vacuum, which implies that it moves more slowly through other media. But if that's the case, then how could the speed of light be constant in vacuum? In other words, if light travels at c through a vacuum, then enters an atmosphere and slows down as a result, it would have to accelerate once it re-entered vacuum. The alternative would be that light doesn't slow down as it passes through a medium, which seems to make the "speed of light in a vacuum" disclaimer superfluous.

Obviously, I'm missing something. Would someone mind filling me in?

Rilke's Grand-daughter · 6 April 2005

AT, you are aware that elapsed time (as measured by a clock) and sidreal time (as measured by days) are entirely different? Or was that remark a joke?

GCT · 6 April 2005

So he's not at home and he knows that his wife is doing something (and he doesn't seem to like it), though he doesn't know exactly the situation. How does he know it?

— Koly
Um, isn't it obvious? The designer told him.

Rilke's Grand-daughter · 6 April 2005

While the resident cognoscenti are fielding questions, would you mind clearing something up for me? I understand that the usual figure for the speed of light is its speed in a vacuum, which implies that it moves more slowly through other media. But if that's the case, then how could the speed of light be constant in vacuum? In other words, if light travels at c through a vacuum, then enters an atmosphere and slows down as a result, it would have to accelerate once it re-entered vacuum. The alternative would be that light doesn't slow down as it passes through a medium, which seems to make the "speed of light in a vacuum" disclaimer superfluous. Obviously, I'm missing something. Would someone mind filling me in?

What's happening is that although the photons always move at c, even in a medium, in a medium, they get absorbed and then re-emitted by the atoms of the medium. That's what accounts for the differential in velocity. The denser the medium, the shorter the distance a photon travels before being absorbed and re-emitted. So, ironically, once could say that photons always move at the speed of light, no matter what the medium, but light doesn't. Does that help?

Colin · 6 April 2005

Absolute Time -

I think I can answer that. As I understand from Dr. Pratchett's research, darkness is much faster than light. (That is why a room with no light source is always dark when you first open the door - all the darkness rushes in ahead of the light.) Because mass increases with speed, darkness is also much heavier than light. As more and more days accrue on mountaintops, the darkness flows downwards, eventually accreting on the ocean floor - this is why the ocean's depths are always dark. The excess light is less dense, and is eventually reflected away by clouds - this is why the tops of clouds, even thunderheads, are always light (except at night, when the falling darkness occludes the light).

Therefore, while extra days and nights are in fact accruing on mountaintops, we never notice it, because the light levels even themselves out. Calendar discrepancies are largely ignored, because no one important lives on mountaintops, except perhaps hermits, who don't use calendars in any event.

Rilke's GD -

Yes, that's as helpful as it is interesting. Thank you very much.

Absolute Time · 6 April 2005

AT, you are aware that elapsed time (as measured by a clock) and sidreal time (as measured by days) are entirely different?

Could you please elaborate? No, it's no joke. Perfectly valid question.

Rilke's Grand-daughter · 6 April 2005

Colin, you worry me... %:->

Koly · 6 April 2005

In other words, if light travels at c through a vacuum, then enters an atmosphere and slows down as a result, it would have to accelerate once it re-entered vacuum. The alternative would be that light doesn't slow down as it passes through a medium, which seems to make the "speed of light in a vacuum" disclaimer superfluous.

— Colin
What happens in matter is that the photons are absorbed by the electrons orbiting the nuclei, these are excited and reemit the photon a little later. This effectively reduces the perceived speed of light when propagating through matter. In reality, photons travel ALWAYS through vacuum, they only interact with charged particles, i.e. are destroyed and recreated.

Koly · 6 April 2005

I am so slow, beaten by RGd...

Rilke's Grand-daughter · 6 April 2005

AT - we'll take the sunrise as a basic measuring point. Now, the interval between sunrises is based purely on the speed of rotation of the earth. The intervals measured by a clock are not connected to this rotation. For example, a clock which measures time in terms of seconds, uses as the duration of a second 9,192,631,770 periods of radiation corresponding to the transition between the two hyperfine levels of the ground state of the caesium-133 atom at zero kelvins - according to wikipedia.
The point is that these two things are unconnected - the speed of rotation of the earth could change and the number of seconds measured by the clock in that day would shorten.

Now what happens in a GR situation is that the 'seconds' measured by a clock at sea-level and a clock on Everest would have different lengths. So the apparent interval in seconds between sunrises would be different depending on what clock you used, but both the sea-level and the Everest clock would experience sunrise at the same 'moment.

Jim Harrison · 6 April 2005

One seldom mentioned consequence of special relativity: as you heat a gas, it becomes heavier because of the greater velocity of the molecules that make it up. To get a measurable effect, you have to have a heck of hot gas because the molecules need to reach near-relatavistic speeds to get appreciably more massy.

Colin · 6 April 2005

Followup question - would light travelling through a medium lose energy, then? Photons exciting electrons into emitting another photon can't (as far as I know) be a free transaction; what is the effect of the energy loss? Does the light move down in the spectrum, or simply become dimmer?

Thanks, by the way, for the answers. Such an interesting thread, bereft of the usual invective.

Koly · 6 April 2005

Could you please elaborate? No, it's no joke. Perfectly valid question.

— Absolute Time
I'll try to help you if I won't be already beaten by someone else by half an hour... What you should do when comparing clocks is to do a measurement in your frame, e.g. you measure that the time between two sunsets is 24 hours. Then compare your results with those in different frames, e.g. your buddy on Mt.Everest measured for the same two events 40 hours (the Earth is veeeeery heavy and the Mt.Everest is extreeemely high). With this definition you should be able to conclude answers for your questions easily.

Koly · 6 April 2005

Damn...

Ok, let's race for the Colin's follow up!

Absolute Time · 6 April 2005

Now what happens in a GR situation is that the 'seconds' measured by a clock at sea-level and a clock on Everest would have different lengths. So the apparent interval in seconds between sunrises would be different depending on what clock you used, but both the sea-level and the Everest clock would experience sunrise at the same 'moment.

So, then what you are saying is that the clock on top of Mt. Everest is running faster, but time isn't. If it were time that was running faster, then events (i.e. sunrises, sunsets) would keep in synch with the faster running clock.

Bayesian Bouffant, FCD · 6 April 2005

Followup question - would light travelling through a medium lose energy, then? Photons exciting electrons into emitting another photon can't (as far as I know) be a free transaction; what is the effect of the energy loss? Does the light move down in the spectrum, or simply become dimmer?

— Colin
Your results may vary. The emitted photon may be the same energy as the initial photon. Or in some cases (fluorescence) a lower energy photon may be emitted. In some cases (multiple photon excitation) you can even get an emitted photon with higher energy than the initial photons, but you end up with a smaller number of photons.

Koly · 6 April 2005

Followup question - would light travelling through a medium lose energy, then? Photons exciting electrons into emitting another photon can't (as far as I know) be a free transaction; what is the effect of the energy loss? Does the light move down in the spectrum, or simply become dimmer?

— Colin
"Free transaction" is not a term used in physics. If an electron absorbs a photon, is excited to a different energy level and then reemits the photon while getting back to the original level (one common situation), the energy of the emitted photon will be exactly the same as that of the absorbed one, because of the energy conservation. However, it's momentum nad thus the direction of propagation can be different. What exactly will happen depends on the matter and the energy spectrum of the light used. You can observe various situations with your own eyes in the visible spectrum: glass does not absorbs too much and let's most of photons through. Mirror absorbs most of the light and reemits it backwards. Black paint absorbs almost all of the ligth and transforms it to heat - the photons are not reemited properly and their energy is transformed into the kinetic energy of the atoms. A blue thing absorbs all of the spectrum except the blue part, which is bounced back. And so on.

Koly · 6 April 2005

Well, whatever... Just hope I am not completely useless here...

Frying Tiger · 6 April 2005

Remember, time always seems to pass at the "normal" rate for you, in your frame of reference. External events (like sunrise/sunset) might measure as taking less or more time depending on where you are in the gravity field, but there is no "absolute" amount of time the event takes... it all depends on where you're observing it from. Yikes! (grin)

Koly · 6 April 2005

So, then what you are saying is that the clock on top of Mt. Everest is running faster, but time isn't.

— Absolute Time
Well imagine my example - a 40 hour day on Mt.Everest would mean your buddy would be very old after 40-50 years (defined as a 365 sunsets, for example). You could watch him age and die, while you would still be only "in the best age". Is his time running faster or not?

Koly · 6 April 2005

Um, isn't it obvious? The designer told him.

— GCT
Well, some call it being jealous... We should ask him whether he has some real data about his wife or he's just jealous, Einstein's Theory of Relativity depends on it!

Scott Simmons · 6 April 2005

"So, then what you are saying is that the clock on top of Mt. Everest is running faster, but time isn't. If it were time that was running faster, then events (i.e. sunrises, sunsets) would keep in synch with the faster running clock."

AT, there's not a short way to explain what's wrong with this without you learning the mathematics of (at least Special) Relativity. But the upshot is that, if you insist on absolute time and say that only clock speeds vary based on changes in reference frame, then you have separate general laws of physics that apply to different frames. Sizes, masses, and electrical charges of real objects will be different depending on which frame they are measured in. Relativistic spacetime provides a single, consistent model that works anywhere in the universe ...

Enigma · 6 April 2005

For example, a clock which measures time in terms of seconds, uses as the duration of a second 9,192,631,770 periods of radiation corresponding to the transition between the two hyperfine levels of the ground state of the caesium-133 atom at zero kelvins

Umm, wouldn't any atom at 0 kelvins have no molecular energy, no vibration? Absolute Zero and all. Was this supposed to be 0 Celsius? Or am I missing something?

Absolute Time · 6 April 2005

you measure that the time between two sunsets is 24 hours. Then compare your results with those in different frames, e.g. your buddy on Mt.Everest measured for the same two events 40 hours

Then the buddy has a clock which is running faster, but his time isn't.

Well imagine my example - a 40 hour day on Mt.Everest would mean your buddy would be very old after 40-50 years (defined as a 365 sunsets, for example). You could watch him age and die, while you would still be only "in the best age". Is his time running faster or not?

Actually no, you and your buddy would still be the same 'age' because time is running at the same speed for both of you.

Absolute Time · 6 April 2005

Well imagine my example - a 40 hour day on Mt.Everest would mean your buddy would be very old after 40-50 years (defined as a 365 sunsets, for example). You could watch him age and die, while you would still be only "in the best age". Is his time running faster or not?

I assume that you believe that both persons have witnessed the same number of sunsets and sunrises, then the buddy's watch is running faster but time is running at the same speed for both.

Maastrictian · 6 April 2005

Absolute Time:

Then the buddy has a clock which is running faster, but his time isn't.

What mechanism would you propose to measure this "time" if not a clock? And by "clock" I mean anything from a pocket watch to a cesium atom. --Chris (first post here for me, hi all)

Maastrictian · 6 April 2005

Absolute Time wrote:

Then the buddy has a clock which is running faster, but his time isn't.

What mechanism would you propose to measure this "time" if not a clock? And by "clock" I mean anything from a pocket watch to a cesium atom. --Chris (first post here for me, hi all)

Absolute Time · 6 April 2005

Well imagine my example - a 40 hour day on Mt.Everest would mean your buddy would be very old after 40-50 years (defined as a 365 sunsets, for example). You could watch him age and die, while you would still be only "in the best age". Is his time running faster or not?

I assume that you believe that both persons have witnessed the same number of sunsets and sunrises, then the buddy's watch is running faster but time is running at the same speed for both.

Flint · 6 April 2005

In Gene Wolfe's book "The Sword of the Lictor" Severian goes to a house where the epoch is different, and more distant, as he ascends to higher floors. Evidently the top floor is some millions of years older than the bottom floor. Clearly, this house has been sitting there a very long time, while the different time rates accumulate.

Absolute Time · 6 April 2005

What mechanism would you propose to measure this "time" if not a clock? And by "clock" I mean anything from a pocket watch to a cesium atom.

If your buddy has a defective watch which is running twice as fast as yours, then does that mean he is undergoing time dilation and time is passing twice as fast for him? I certainly should hope not. Yet, he will count 48 hours as the length of each day while you are only counting 24.

steve · 6 April 2005

Comment #23583 Posted by Absolute Time on April 6, 2005 03:00 PM (e) (s) So, then what you are saying is that the clock on top of Mt. Everest is running faster, but time isn't. If it were time that was running faster, then events (i.e. sunrises, sunsets) would keep in synch with the faster running clock.

Where do these people who have no physics education get the hubris to criticise the consensus views of the physics community? Is it the same place the anti-evolution people get their hubris? Do they realize how unlikely it is that their layman's complaints are correct? They must not. If you think that you know how einstein was wrong with Relativity, and have no physics education, or if you think you know how darwin was wrong with evolution, and have no biology education, reconsider your belief.

Greg · 6 April 2005

Can I just say that this is science at its finest. I mean it. I loved this. Not only did I learn plenty, but it was a thoughtful, concise, information-packed, convivial thread. Thanks to all!

Ken Shackleton · 6 April 2005

I assume that you believe that both persons have witnessed the same number of sunsets and sunrises, then the buddy's watch is running faster but time is running at the same speed for both.

— Absolute Time
The reason why his watch runs faster is because time is running at a different rate for him and his watch [since they are located at the same reference and that reference is different from the person in the valley, per the example]. He experiences 40 hours from sunrise to sunrise at the mountain-top [per the example], and so grows older each day [solar day] than someone that only experiences 24 hours from sunrise to sunrise.

Henry J · 6 April 2005

Re "So, then what you are saying is that the clock on top of Mt. Everest is running faster, but time isn't."

That's my understanding of it, too. Another way of looking at it would be to say that a strong gravity field causes physical processes to take longer (not just clocks). My way of explaining that to myself is to figure that in stronger gravity (or at really high speeds), photons take longer to get from one atom to the next, and the physical processes with which we deal pretty much depend on those exchanges of photons. Ergo, stuff takes longer in those situations.

Henry

Colin · 6 April 2005

Steve, knowledge has no bearing on truth - this can be empirically proven. Knowledge, of course, is power, which is also energy. And Einstein showed that energy is matter, which has mass. This demonstrates two things - that increasing knowledge increases the knower's mass, and that knowledge is a concrete, physical thing. (It also demonstrates, according to the classic proof, that libraries are dangerous places, due to the enormous weight of accumulated knowledge, but that is neither here nor there.)

Truth, on the other hand, is beauty. And beauty, being an abstract concept, is both unburdened by mass and an essentially subjective quality. After all, beauty, and therefore Truth, is in the eye of the beholder.

Increasing knowledge increases mass, but does not increase the unrelated value of Truth. The addition of mass does weigh down the knowledgable observer, however, who also experiences a faster flow of time and thus aging due to the increased time-space dilation of his own gravitational field.

This is why knowledgable men and women seem more mature, and often feel old, weighed down, and tired when confronted with those who are burdened only by their own subjective Truth.

steve · 6 April 2005

The clock is running faster. Time is running faster.

Paul Flocken · 6 April 2005

Comment #23613 Posted by Maastrictian on April 6, 2005 04:29 PM (e) (s)

Absolute Time: Then the buddy has a clock which is running faster, but his time isn't. What mechanism would you propose to measure this "time" if not a clock? And by "clock" I mean anything from a pocket watch to a cesium atom. ---Chris (first post here for me, hi all)

Try using heartbeats for your clock. I have learned that people who don't understand relativity think that if it is their reference frame that is running slower then they would be able to see it. Using heartbeats has helped me explain that they run slower too. Don't forget to point out that events outside the slower reference frame would appear to run faster to the person who is "slowed".

Where do these people who have no physics education get the hubris to criticise the consensus views of the physics community? Is it the same place the anti-evolution people get their hubris? Do they realize how unlikely it is that their layman's complaints are correct? They must not. If you think that you know how einstein was wrong with Relativity, and have no physics education, or if you think you know how darwin was wrong with evolution, and have no biology education, reconsider your belief.

Steve that was uncalled for. Civil questions were being asked and civil answers were being given. Understanding was coming about. What more could you ask for? Sincerely, Paul

Paul Flocken · 6 April 2005

Comment #23635 Posted by Colin on April 6, 2005 05:21 PM (e) (s)

Steve, knowledge has no bearing on... ... ...dilation of his own gravitational field. ... ...only by their own subjective Truth.

Colin, you need to take that on the road. I thought the first post above was only a one-off, but I fell on the floor when I read this one. Are you responsible for the "Hotter then hell" thermodynamics jokes? I ahve seen two of them over the years. ROFLM(vestigial tailbone)O ;^) Paul

Absolute Time · 6 April 2005

So, then what you are saying is that the clock on top of Mt. Everest is running faster, but time isn't. If it were time that was running faster, then events (i.e. sunrises, sunsets) would keep in synch with the faster running clock. Where do these people who have no physics education get the hubris to criticise the consensus views of the physics community? Is it the same place the anti-evolution people get their hubris? Do they realize how unlikely it is that their layman's complaints are correct? They must not. If you think that you know how einstein was wrong with Relativity, and have no physics education, or if you think you know how darwin was wrong with evolution, and have no biology education, reconsider your belief.

OK Steve, if a clock is running faster, but events don't keep in synch with the faster moving clock, then how is this different from simply having a fast running clock?

steve · 6 April 2005

Read a book or two about relativity. or the relevant chapters from a textbook of Modern Physics. Or check out any number of websites. Or ask Paul.

Paul Flocken · 6 April 2005

Comment #23640 Posted by Absolute Time on April 6, 2005 05:47 PM (e) (s)

OK Steve, if a clock is running faster, but events don't keep in synch with the faster moving clock, then how is this different from simply having a fast running clock?

AT you need to specify which events so that you know which reference frame, and it wouldn't just be the clock you are holding, YOU would also be running slow or fast, but you would feel completely normal, and the clock you are holding would look completely normal. Only the person outside your frame could tell what was happening to you. Paul

gav · 6 April 2005

Ah, I see. Time goes faster as you get older because your mass increases. But wouldn't days sitting on top of Mount Everest be interminably long?

Malkuth · 6 April 2005

I apologize if this is an ignorant question, but...

Isn't the speed of light in any medium (including a vacuum, which I probably shouldn't be calling a medium) dependent on the permittivity and permeability of that medium? The permittivity in a vacuum is supposedly due to the virtual particle-antiparticle pairs that occur in it, which can absorb and re-emit photons. If there are less particle-antiparticle pairs, then there should be a lower permittivity, and higher speed of light.

There was a paper by a Klaus Scharnhorst on it ( http://arxiv.org/abs/hep-th/9810221 ), but I don't believe I know enough about physics (alas, I am only a layman) to judge the hypothesis. But I've read elsewhere that there was a measured difference in the speed of light (didn't get the exact measurement).

I'm wondering if Scharnhorst's hypothesis is valid, and how Special Relativity works out if the speed of light can be made faster or slower?

Again, I apologize if this is an ignorant question.

Stan Gosnell · 6 April 2005

Yes, just as being a vegan teetotaler causes time to move very slowly. You don't actually live longer, it just seems like it. And you don't enjoy the time you do live. As the saying goes, time goes faster when you're having fun.

Patrick Harris · 6 April 2005

OK Steve, if a clock is running faster, but events don't keep in synch with the faster moving clock, then how is this different from simply having a fast running clock?

That is one reason why we make a distinction between sidreal time and elapsted time. Sidreal time is based on the axis or rotation of the earth. For everone in all time frames sidreal time is the same. The Earth turns once every day. However.......depending you your specific frame of reference the elaptsed time that rotation took will be different. For someone standing on the equater at sea level one sidereal day take approximately 24 hours. For someone at the north pole, on mount everest or the mood it would take less time because IN THEIR FRAME OF REFERENCE time is faster. This is what Mr. Stenger meant by saying reltivity was counter intuitive. We all live in our own frame of reference and very seldom realy see any instances of time dialation. I work in satellite communications. We have many timeing systems that must be synched together to insure the comm system runs properly. I experince the effect of reletivity because the clocks onboard the satellites in orbit run faster than the clocks on the ground stations. It is hard to grasp this concept because we are never out of our personal frame of reference and very seldom have interactions with anyting outside or frame.

bill · 6 April 2005

Although I would hesitate to call Mr. Richards an arrogant moron, mainly because I have no evidence whatsoever that he is arrogant, I do find his "analysis" to be both ethically and intellectually bankrupt. Personally, I have no interest in vacuuous rantings as posited by Mr. Richards who evokes only two emotions: laughter and pity. Aside from the sport, I fail to understand why we joust with such intellectual lightweights as Richards.

All this blather reminds me of the 1986 Challenger report in which Richard Feynman said, essentially, that it doesn't matter what the committee decides by vote, the fact is that if the shuttle is launched in freezing weather it will blow up. Physics trumps policy.

It doesn't matter what Dembski or Behe or Wells or any of the IDiots say, the Universe is the way it is. Physics trumps ideology.

Josh Narins · 6 April 2005

Professor Perakh,
You are right to the extent that the childish grasp, no, not grasp, the misunderstanding of these loons makes any form of discussion an endeavour bound to be mired a host of problems...
And yet, the general public (of which I certainly am, although I did take four semesters of college Physics) has _no_one_ but the most learned, such as yourself, to rely upon.
As far as I can tell the anti-scientific/pro-religious sentiment is reaching all time highs, and is empowered by the wealth and power of the American State. Ggabo of Cote D'Ivoire, for example, at least _pretends_ to be a religious nut for the money/political leverage.
I sympathize with your wishing these morons away, but I believe it is your duty to society itself which demands that you, instead, confront them.
Or, if you have the means, pay someone to do it for you.

Neo-university student · 7 April 2005

When I was a teenager and slightly older I had no problem with getting rid of absolute time and I did not mind an expanding universe one bit and I was willing to give Albert Einstein the benefit of the doubt given that his theories have stood the tests of time, criticism and rigorous experiments. I set off to see if I could get a handle on the theories of Relativity. Sure, I had no hope of getting into the math but there were plenty of laymen type books at the library; I had always loved science. How hard could it be?

Several books later and after three periods of giving up, I got to the point where it all seemed to make sense. My point is that, while you can get a simple understanding of the theory without having the math to actually use it to do science, it requires finding a few good books and slogging through. An online discussion may be helpful but it won't give you a good understanding of the theory. I would also suggest approaching the subject as if it were true while learning about it.

If you can accept a theory temporarily you can ask if it makes sense AFTER you understand it. If it does not make sense, you have the knowledge to state why. That is one reason why none of these Panda's Thumb people ever get converted or even "baffled/silenced". They have looked into all the "theories" (meaning the one theory that evolution is not true) and found the consequences to be ludicrous in the face of the observable evidence and reason. Creationism when combined with knowledge form many branches of science draws the conclusion of a God who makes mistakes and oversights when he creates. It requires a God who plants false evidence and needless coincidences which support evolution in every layer of reality to make us doubt him and who sees faith in things that are perfectly designed by him to look false as a positive thing. While it may be consistent with the God of the "scriptures", it is a nightmare belief for a thinking human being.

Nick · 7 April 2005

However, I think I see the point he is trying to make. It is true that an observer moving at a speed near the speed of light relative to Earth would in fact measure a very small time since the big bang.Vic Stenger

Well, I guess I didn't come off too bad with my vague understanding, even when Vic Stenger was thinking of me as an IDist. It would be interesting to get Stenger comment directly on Richards's blog post.

Marek14 · 7 April 2005

Different speed of time on the sea level/Mount Everest is a prediction of General Theory of Relativity. I think that it's neccessary to understand the Special Theory before one tackles this one.

And the Special Theory, as I understand it (and I might be wrong), has only two prerequisites:

1. All frames of reference for observers that travel at uniform velocity relatively to each other are EQUIVALENT (i.e. there is no way how to ascertain if your frame of reference is in rest or uniform motion, unless you look out).

2. Speed of light is constant in every frame of reference.

It's this second notion that is hard to grasp, since it has lots of counter-intuitive results.

General Theory of Relativity adds a third prerequisite which I think goes something like that:

3. A frame of reference undergoing acceleration due to gravitational force is indistinguishable from the frame of reference that is in rest or uniform motion. (again, this holds for observer IN the frame).

Is this generally or specially correct?

Russell · 7 April 2005

I fail to understand why we joust with such intellectual lightweights as Richards... It doesn't matter what Dembski or Behe or Wells or any of the IDiots say, the Universe is the way it is. Physics trumps ideology.

— Bill
Yes, but unfortunately there are a lot of school boards, deciding on curricula, that take these guys seriously. Sure, it's "intellectual slumming" to engage these guys, but think of it as your civic duty. Something like jury duty.

Ginger Yellow · 7 April 2005

Is it not that a frame of reference undergoing (a given) acceleration is indistinguishable from a frame of reference "at rest" but subject to (a given) gravitational force? Or conversely, freefall in space is actually inertial motion while "standing still" on the earth's (or technically something massive that isn't spinning's) surface is accelerated motion.

GCT · 7 April 2005

Isn't the speed of light in any medium (including a vacuum, which I probably shouldn't be calling a medium) dependent on the permittivity and permeability of that medium? The permittivity in a vacuum is supposedly due to the virtual particle-antiparticle pairs that occur in it, which can absorb and re-emit photons. If there are less particle-antiparticle pairs, then there should be a lower permittivity, and higher speed of light. There was a paper by a Klaus Scharnhorst on it ( http://arxiv.org/abs/hep-th/9810221 . . . ), but I don't believe I know enough about physics (alas, I am only a layman) to judge the hypothesis. But I've read elsewhere that there was a measured difference in the speed of light (didn't get the exact measurement). I'm wondering if Scharnhorst's hypothesis is valid, and how Special Relativity works out if the speed of light can be made faster or slower? Again, I apologize if this is an ignorant question.

— Malkuth
It seems that no one has taken up your question yet. It's not ignorant. The first time I saw an index of refraction curve for a glass that dipped below 1, I had the same question. I found a pretty good article that doesn't get too in depth here that will probably help you out.

Richard Lionhart · 7 April 2005

These ID proponents would do well to take the Annenberg/CPB video class "The Mechanical Universe" in it's entirety. These classes are available online, are free, and illustrate Einstein's and others theories perfectly. To prove if they understand the material, ask them if they would like to retract their statement. If no, then its back to class. Lather, rinse, repeat.

There is an unwritten law regarding kooks. Sure signs you are reading nonsense from a kook are when they claim a) Einstein was wrong, or b) there is a lumineferous ether.

"Physics is just a bunch of theories."

Josh Narins · 7 April 2005

Those Annenberg/CPB tapes are usually very expensive. I'm not sure if they are free to certain, qualifying academic institutions or not, but I had to pay 45$ plus shipping for one episode of one of the math shows.

Josh Narins · 7 April 2005

If the universe if 13.7 billion years old from our reference frame, from where does the universe appear oldest? What would that time mean? Would there be some utility to finding what time this was?

Alex Merz · 7 April 2005

Does Netflix have the Annenberg/CPB tapes? That would reduce costs substantially.

Henry J · 7 April 2005

Re "3. A frame of reference undergoing acceleration due to gravitational force is indistinguishable from the frame of reference that is in rest or uniform motion. (again, this holds for observer IN the frame)."

Add one condition here: acceleration pushes the whole object in the same direction. Gravity pulls the whole object toward a point, which means that it also, to some extent, pulls the sides of the object toward each other. If the object is large relative to the distance from the gravity source, that effect could be measurable.

Henry

Malkuth · 7 April 2005

It seems that no one has taken up your question yet. It's not ignorant. The first time I saw an index of refraction curve for a glass that dipped below 1, I had the same question. I found a pretty good article that doesn't get too in depth here that will probably help you out.

— GCT
Yes, that is helpful. Thank you. Would the 'c' that's to be used in Einstein's equations be the speed of light if there were absolutely nothing interrupting the light, then? That is, the speed at which a photon travels without being absorbed and re-emitted by virtual particle-antiparticle pairs? Rilke's Grand-daughter had said that it's photons that always move at the constant speed of light, but not necessarily "light" because the constant-speed photons can be absorbed and re-emited by atoms in a medium (which takes time). Could the same thing by said of a vacuum? That, because a vacuum has virtual particles and antiparticles which "slow" light, the speed of light in it is not necessarily equal to the constant speed of a photon? Or am I incorrect in assuming that the virtual particle-antiparticle pairs absorb and re-emit photons?

Henry J · 7 April 2005

I wonder if that ties in with something I read a few months ago, about the speed of light varying a very slight amount with frequency. Would some frequencies be more prone to absorption/reemission than others? (I forget which end of the spectrum it said was slower than the other.)

Henry

Ed Darrell · 7 April 2005

Um, correct me if I'm wrong, but didn't Einstein just pick a very large number? Is the speed of light actually relevant to the equation?

Randall Wald · 7 April 2005

Ed, which equations are you referring to? E = m*c^2? Gamma = 1/(c^2 - v^2)? (I may have that one wrong, but it definitely has a c in it.) C comes up in many equations of relativity.

Oh, and while it's true that gravitation from a point source looks different than acceleration to something large and close to the point source, that's not really important, since it would be most accurate to say that in general, gravitation from a planer source is indistinguishable from acceleration, and the point source is a degenerate case.

And I'm fairly certain that the speed of light is computed with the vacuum permittivity in mind, so that it assumes absorption/re-emission from virtual particle/anti-particle pairs. Either that, or the virtual particles don't absorb light, but I doubt it.

As for the age of the universe: It really doesn't matter how old the universe appears in other reference frames. If you had been constantly accelerating (or in a deep gravity well) since the Big Bang, you'd think the universe was a lot younger than we on Earth do; this would have no importance for cosmology. For someone to think the universe is older than we on Earth do, they'd need to have been in constant motion (i.e., not accelerated and not in a gravity well) for all time; I'm not sure how much longer they'd think the universe is, but again, it really doesn't matter.

GCT · 7 April 2005

Disclaimer: I'm not claiming to be an expert on this, so anyone can correct me if I'm wrong, but here goes.

Malkuth, I believe that c is always 3x10^8, which is the speed of light in a vacuum. I don't think that one can slow down light in a vacuum.

Henry J, the index of refraction does vary depending on frequency, which does affect the speed of light traveling through a medium. Usually, it's said that the light travels at the speed c/n (which is the phase velocity I believe.) I'm not sure if some frequencies are more prone that others per se; I think it depends on the material the light is propagating through.

GCT · 7 April 2005

Oops, bad scientist...that's c=3x10^8 m/s.

Julian · 7 April 2005

I believe that higher frequencies of the EM spectrum experience a greater decrease in velocity and thus refractive indices increase with frequency. I'm not sure though...

plunge · 7 April 2005

"If the universe if 13.7 billion years old from our reference frame, from where does the universe appear oldest? What would that time mean? Would there be some utility to finding what time this was?"

While I can't answer your question, the problem I have as a non-physicist answering your question might be helpful. The problem I have is that I ask myself "oldest compared to what?" Remember that relativity says that two people passing by each other in space at near light speed will BOTH see the clocks of the other as being slow. Now, if I wanted to think of what would experience the universe as being really really old, I'd want to pick a vantage point from which the universe's speed appeared to be at a maximum to myself. Imagine if I wanted to see a clock on a certain train as going the slowest as possible from the vantage point I pick. I could pick a point along the path of the train, but what if the path is moving too (say, the train is on an asteroid zooming through space). So maybe I could pick a point in space on which both the train and the asteroid its on appear to be moving. That would make the train appear to be going REALLY fast, and its clock really slow. I could even move myself in the opposite direction of the asteroid and the train. But for the universe, where in the heck would that place be? How would I move? The universe is expanding away from me EVERYWHERE, from ANY point I pick. So I wouldn't be able to play the same tricks to make it look faster (and hence slower) to myself.

Maybe that was all wrong and goobledygook, but for an amatuer trying to think about relativity, that's why the question ties my head in knots.

Which is exactly why I'm not likely to be the sort of person who goes "I think I just disproved Einstein!"

Henry J · 7 April 2005

I was talking about through space, not through what we think of as a medium. Some article gave the idea that light from other galaxies might show a slight difference in arrival time based on its frequency. I don't know if the idea held up or not (or whether it's even been tested). Also don't know if it was based on there being some interference from particles along the route, whether scattered matter or the occasional virtual particle.

Mark Perakh · 7 April 2005

Re: Comment 23680 by Josh Narins.
Dear Josh: I agree with you that exprts indeed must spend some time and effort explaining to laymen the basic facts of science. I believe, though, that I have a valid excuse for not actively taking part in the discussion on this thread. I have had a surgery recently and it is difficult to me to type as my shoulder is bandaged.

Regarding my general obligation to share my experience with general public, perhaps it is relevant to point out that I am over 80 years old and that when I already was 80, I wrote and published a book over 400 pages long (titled Unintelligent Design) where I did my best to reveal the emptiness and futility of the ID concepts.

Since there are many well substantiated comments on this thread elucidating various subtleties of relativity, I'll comment now on only one question asked by Enigma (comment 23608) to which nobody has so far offered a response. First, zero Celcius is not the absolute zero but 273.16 Kelvin above absolute zero (or you can say that absolute zero is at -273.16 Celsius). Second, even at absolute zero of temperature the particles (such as electrons) possess energy which is not zero (it is callled the ground state - which is the minimal energy a particle can possess). Furthermore, absolute zero is unattaninable (the 3rd law of thermodynamics) although it can be approached infinitely close. What is zero at absolute zero of temperature is the system's entropy (although it is just a theoretical limit as the absolute zero is practically unattainable).
Cheers, Mark Perakh

Henry J · 7 April 2005

Re "I believe that higher frequencies of the EM spectrum experience a greater decrease in velocity and thus refractive indices increase with frequency. I'm not sure though..."

That would make sense I guess, if one presumes that each wave cycle has an equal chance of interacting with a real or virtual particle that happens to be at that location, so more waves per unit distance = greater slowdown.

---

I wonder if a clock (or any physical process) deep inside the Earth would run faster or slower than the same thing sitting on Earth's surface. (Weight drops as one goes from surface toward the center; something at the center is pulled equally in all directions and thus weightless, even if squashed from all the pressure.)

Henry

Randall Wald · 7 April 2005

A clock at the center of the planet would indeed run faster than one on the surface -- at least, based on the GR effects. If you're comparing it with a clock on the equator (or anywhere that's not a pole, really), you've also got SR effects, and need to ask which frame you're looking from.

Realistically, though, the difference would only matter if you're trying to position satellites or something, which isn't likely to happen at the center of the Earth.

Chris B · 7 April 2005

So a rise in sea level to closer to Everest would give us longer days. Is this a reason for defending, or attacking, global warming?

BlastfromthePast · 8 April 2005

Let me wade in here. First, I've read Richards' article (listed somewhere above), and it appears that he misunderstands what is meant when it is stated that there is no "absolute time."

To have "absolute time", you need an "absolute" frame of reference. Einstein's theories (both special and general) start with the premise that (1) there is NO "absolute frame of reference", and hence (2) all is relative. To deny that there is no "absolute" time, is not to deny that something such as "time" exists. So Richards just simply misunderstands what Einstein was after. I can't defend that. But, judging from the posts, it seems like a lot of people don't understand Einstein either. This is not surprising, and should not be used, IMHO, against Richards like a dagger.

Further, let me point this out. The idea that Einstein had concerning the absence of "absolute" frame of reference came from science's begrudging abandonment of the idea of an "ether", which was so central to the work of Maxwell on electricity and magnetism. The coup de gras that "axed" the "ether" was the Michelson-Morley experiment, ca. 1875. That experiment purportedly showed that light travels at the same speed no matter at what its direction relative to the supposed "ether." Interestingly, in the latest two issues of New Scientist, there have been two articles dealing with the possible reemergence of the "ether", one article dealing with a proposed experiment to double check the Michelson-Morley experiment.(and which talks about seemingly valid mathematical arguments disputing Michelson-Morley's results.)

I personally find it very hard to believe that something like an "ether" doesn't exist. But even if an "absolute frame of reference" exists, that doesn't mean that Einstein's theories are wrong; only that they have to be reformulated. Einstein assumed that space was both "homogeneous" (i.e., the same everywhere) and "isotropic" (i.e., there is no preferred 'direction). If there is an "ether", then "isotropy" has to go; but the theories do not!

Here's what Einstein himself had to say about this: (from "The Meaning of Relativity")

"The laws of physics could be expressed, even in case there were a preferred direction in space . . . If there were a preferred direction in space it would simplify the description of natural phenomena to orient the system of co-ordinates in a definite way with respect to this direction. But if, on the other hand, there is no unique direction in space, it is not logical to formulate the laws of nature in such a way as to conceal the equivalence of systems of co-ordinates that are oriented differently." (p. 16, footnote)

Zim · 8 April 2005

Hi, everyone.

A clock at the center of the planet would indeed run faster than one on the surface...

— Randall Wald
Not if I understand GR correctly. GR extends the interpretation of E=mc^2 to include gravitation. So gravity accelerates light as well as matter, and climbing out of a gravitational well requires energy. Now since a photon can't be slowed down, the energy change is exhibited as a change in the frequency of the photon, the frequency being proportional to the energy. So a photon climbing up the well from the centre of gravity to the surface would have a lower frequency at the surface than that observed at the centre. Clocks at the centre would therefore have a similarly lower frequency, i.e., run slower, when observed from the surface.

plunge · 8 April 2005

"I personally find it very hard to believe that something like an "ether" doesn't exist."

Wow! Just submit that brilliant sentance to a journal of physics as an entire article, and you're set for life. Nobel Prize for you!

David Heddle · 8 April 2005

plunge,

You shouldn't be so sarcastic. The Higgs field is very aether-like.

Koly · 8 April 2005

I'll try to answer two questions, first the propagation of light through vacuum and the question of where most time has past from Big Bang. It has to be said that both need quite nontrivial amount of insight to relevant theories (Quantum Electrodynamics and GTR) to understand properly, but I'll do my best to keep things as simple as possible. It will be a tough exercise in compromizing simplicity and retaining at least a little bit of accuracy.

Would the 'c' that's to be used in Einstein's equations be the speed of light if there were absolutely nothing interrupting the light, then? That is, the speed at which a photon travels without being absorbed and re-emitted by virtual particle-antiparticle pairs? Rilke's Grand-daughter had said that it's photons that always move at the constant speed of light, but not necessarily "light" because the constant-speed photons can be absorbed and re-emited by atoms in a medium (which takes time). Could the same thing by said of a vacuum? That, because a vacuum has virtual particles and antiparticles which "slow" light, the speed of light in it is not necessarily equal to the constant speed of a photon? Or am I incorrect in assuming that the virtual particle-antiparticle pairs absorb and re-emit photons?

This is a highly nontrivial question. First of all, what are those virtual particles? In a quantum field theory you have a set of interacting fields, their excitations with a given energy and momentum can be interpreted as particles. Because this is a quantum theory, you can set up the particles and then observe the result, but there is not too much sense in asking how exactly they interacted. The probability of the outcome is a result of a calculation where all possible intermediate states are taken into account. These are the virtual particles. The question whether photons really propagate at 'c' is equivalent to whether this effect causes photons to effectively gain mass. The result of the calculation, part of a program called renormalization, is that though the contribution of the virtual intermediate states renormalize the electromagnetic field, they give no mass. The reason can be tracked back to the gauge symmetry on which the electromagnetic interaction is based. So, both the underlining field and the observed photons are massless in Quantum Electrodynamics. Of course, as always in science, future discoveries could change things, but this is our current theory which agrees with experiment very well. In the other case, the speed of light would indeed slightly depend on frequency.

If the universe if 13.7 billion years old from our reference frame, from where does the universe appear oldest? What would that time mean? Would there be some utility to finding what time this was?

The cosmological models in GTR are derived from the assumption that the universe is homogeneous and isotropic. That means that, in the big scale of things, wherever one is and whatever direction is looking one should see the same thing (some galaxies). Then it is convenient to choose the time coordinate in a special way, so that for any fixed time, the space-time manifold is homogeneous and isotropic. This is what astrophysicists mean when they talk about the age of the universe. The interpretation of this time coordinate is such, that it is the time of an observer which is not moving relatively to the matter background. This matter background is homogeneous and isotropic and determines the space-time geometry, so it makes good sense. So, put simply, you observe the most time from Big Bang when you are standing still compared to distant galaxies, or more accurately, the distant galaxies move all about the same compared to you. If you move in any direction, the time dilatation kicks in and your clock is ticking slower. If one wanted to be very pedant, he could imagine a situation, when the local clock would be moving more quickly, but that would violate homogeneity and isotropy. But that situation is quite real, appears to me. It could be, for example, when some region in the universe would be more empty than the average, e.g. an empty space among clusters of galaxies. However, as our universe is nearly flat anyway, the difference is probably very small.

Koly · 8 April 2005

So a photon climbing up the well from the centre of gravity to the surface would have a lower frequency at the surface than that observed at the centre. Clocks at the centre would therefore have a similarly lower frequency, i.e., run slower, when observed from the surface.

— Zim
Yes, exactly. The red shift does not depend on the stregth of the gravitational field, but rather on the potential. More accurately on the time-time element of the metric tensor. So indeed, in the center of the Earth the time would be ticking slower, even when there is no gravitation there.

Red Right Hand · 8 April 2005

Don't look now, but that ID post on Einstein has just been "disappeared".

Russell · 8 April 2005

... that ID post on Einstein has just been "disappeared".

I wondered how long that would take. If you follow that link now you get "sorry, there is no post to display..." No explanation, no apology for promulgating comically wrong science, no acknowledgment of all those trackbacks that pointed out the error (some more gently than others). And, of course, as we learned from Paul Nelson, the lack of opportunity for comments is purely a technical matter. Next we'll read that the whole thing was a fabrication by Darwinists to make the DI look bad.

Henry J · 8 April 2005

Re "So a rise in sea level to closer to Everest would give us longer days."

By a tiny fraction of a second. Hardly relevant to climate change.

---

Re "That experiment purportedly showed that light travels at the same speed no matter at what its direction relative to the supposed "ether.""

Didn't the math imply that, even before the experiment was performed? As I understand it, the equations for EM could (even then) be solved for c, and the solution came out as a constant.

---

Henry

Malkuth · 8 April 2005

This is a highly nontrivial question. First of all, what are those virtual particles? In a quantum field theory you have a set of interacting fields, their excitations with a given energy and momentum can be interpreted as particles. Because this is a quantum theory, you can set up the particles and then observe the result, but there is not too much sense in asking how exactly they interacted. The probability of the outcome is a result of a calculation where all possible intermediate states are taken into account. These are the virtual particles. The question whether photons really propagate at 'c' is equivalent to whether this effect causes photons to effectively gain mass. The result of the calculation, part of a program called renormalization, is that though the contribution of the virtual intermediate states renormalize the electromagnetic field, they give no mass. The reason can be tracked back to the gauge symmetry on which the electromagnetic interaction is based. So, both the underlining field and the observed photons are massless in Quantum Electrodynamics. Of course, as always in science, future discoveries could change things, but this is our current theory which agrees with experiment very well. In the other case, the speed of light would indeed slightly depend on frequency.

— Koly
It's unfortunate, then, that my understanding of quantum mechanics is only trivial. From my understanding, there are particle-antiparticle pairs that appear in a vacuum and exist for an incredibly short amount of time, after which they annihilate with each other. They can also exist in the intermediate stages of a phenomena, but don't exist in the initial or final state, which is why they're called virtual particles. At least, to my trivial understanding. Is this at all correct?

Randall Wald · 8 April 2005

Yes, exactly. The red shift does not depend on the stregth of the gravitational field, but rather on the potential. More accurately on the time-time element of the metric tensor. So indeed, in the center of the Earth the time would be ticking slower, even when there is no gravitation there.

— Koly
Hmm. That seems counterintuitive, at least. I know that a clock closer to a black hole will tick more slowly than one distant from the black hole. Still, isn't the person at the center of the earth allowed to think that he's floating in open space? I mean, how could he tell either way? Perhaps my problem is that I'm viewing things too absolutely; I think that to figure out your clock's rate, you need only calculate how much acceleration/gravity you're feeling, and you know how your clock ticks with respect to an open-space (no acceleration) clock. Is your depth in a gravity well the important thing, or is it the slope of the well at your point? (Actually, that last sentence may not make sense, but it sounds cool.)

Henry J · 8 April 2005

Seems like at the center of the planet, the "slope" of the gravity well would be zero. But if clocks (i.e., any physical process) run slower there too, it kind of undoes my previously mentioned way of understanding the time slow-down at or above the surface of the planet. (That is, in the middle of the planet, photons don't have to travel a longer distance to get from atom to atom, so that can't be used to explain the time dilation there.)

Henry

Matt Young · 8 April 2005

Don't look now, but that ID post on Einstein has just been "disappeared".

It was there a minute ago, with an update.

Zim · 8 April 2005

Is your depth in a gravity well the important thing, or is it the slope of the well at your point? (Actually, that last sentence may not make sense, but it sounds cool.)

— Randall Wald
Yes, it does sound cool. :-) It's the depth in the well that counts, relative to the depth of the observer. The acceleration due to gravity is a function of the slope, but has nothing to do with the actual, observed time dilation, except to indicate how quickly it changes as you move towards or away from the local centre of gravity.

Koly · 8 April 2005

It's unfortunate, then, that my understanding of quantum mechanics is only trivial. From my understanding, there are particle-antiparticle pairs that appear in a vacuum and exist for an incredibly short amount of time, after which they annihilate with each other. They can also exist in the intermediate stages of a phenomena, but don't exist in the initial or final state, which is why they're called virtual particles. At least, to my trivial understanding. Is this at all correct?

— Malkuth
Well, this is correct in the sense that it is the popular interpretation of the underlining mathematics. You have to understand that the theory is not about virtual particles, etc. What is really there is a set of quantum fields. You have a calculational procedure which is used to get observable predictions from the theory, like decay rates and scattering cross-sections. This procedure allows for such an interpretation, but one could also say "well this is nothing else than a calculation, what matters is the result, so what sense does giving catching names to the used tools have?" We have to be aware that what we want to do is science. Talking about virtual particles is popular and all, but it's not a prediction that could be tested. It's a nice label for the mathematics used to get the result. When I say "two point Green's function consisting of two fermion field propagators" instead of "virtual particle-antiparticle pair" it doesn't sound as good, does it? It's quite sad that what often gets to the public are these popular interpretations and labels physicist often use for hard to grasp phenomena, but not the science itself. Then we, theoretical physicist, look like fools fantasizing outside of reality. This could not be more further away from thruth, when not counting Superstring Theory, which is outside the realm of experiments so far. The photon propagator is a nice example of how things work. When we want to answer the question, whether the photon is massless or not (and thus propagates with velocity 'c'), you have to calculate the various algebraic contributions to the propagator function. You can label them "a pair of virtual electron-positron pair" etc., but that's not important. What is important, that you don't get any contributions to the mass term and thus you predict that the photon is indeed massless. That can be tested in experiment and if it's falsified, then all Quantum Electrodynamics or maybe Quantum Field Theory as a whole with the fancy virtual particle interpretation is crap. However, after many decades of experiments, it wasn't falsified yet, quite the contrary, it's precision in agreement with experiments is unmatched in the history of science.

Koly · 8 April 2005

Hmm. That seems counterintuitive, at least. I know that a clock closer to a black hole will tick more slowly than one distant from the black hole. Still, isn't the person at the center of the earth allowed to think that he's floating in open space? I mean, how could he tell either way? Perhaps my problem is that I'm viewing things too absolutely; I think that to figure out your clock's rate, you need only calculate how much acceleration/gravity you're feeling, and you know how your clock ticks with respect to an open-space (no acceleration) clock. Is your depth in a gravity well the important thing, or is it the slope of the well at your point? (Actually, that last sentence may not make sense, but it sounds cool.)

— Randall Wald
Zim answered your question nicely (and it was right to the point btw), but I want to give you an intuitive understanding what's going on. And I hope it will help Henry too. The whole time dilatation in GTR is quite a simple thing. It's not about time really, it's about observation. So imagine a gravitational well and any ordinary hole is such a well. If you want to get a ball out of the whole, you kick it, but it will slow down when moving out. If you have several balls and you kick them quickly, they quite slow down when getting out of a deep whole. Your buddy catching the balls up there does not have to be very fast to manage it. Of course, you can say, yes the balls loose quite much of their velocity, but when I shoot from a gun, buddy won't make it. But still, even the bullets slows down a little bit. Everything appears to be slower, when observed outside of the whole. Everything? Light does not slow down, does it? No, but even light has to use some of it's energy to get out of the hole. It looses frequency and the result is longer wavelength. But when the wavelength is longer and the velocity is the same, it takes MORE time from the arrival of one peak to another. So even when your buddy is watching you kicking the balls, it appears to him an extremely little tiny bit that you do it slower. So if the hole is deep enough, your buddy will comfortably catch the bullets from your gun. And if it is even more deep, your buddy will watch your slowed down version down the hole. And this is it really. One would be tempted to say that it is only a trick, the time is the same. But when you jump into a black hole, the well is so deep that you will observe the complete future history of the universe. Better think about it like time running with a different pace, because if there is going to be a Big Crash, it will catch you. Even if you stop your fall sooner and get back, all of your buddies will be long gone.

Koly · 8 April 2005

Well, and please ignore my spelling and grammar errors, my English still doesn't seem to be up to par...

steve · 8 April 2005

Comment #23933 Posted by Matt Young on April 8, 2005 02:43 PM (e) (s) Don't look now, but that ID post on Einstein has just been "disappeared". It was there a minute ago, with an update.

His Update should be subtitled "Wherein I contradict myself regarding whether I think Einstein was wrong." It's a pretty awful essay, made awfuler by the update.

Randall Wald · 8 April 2005

Let me clarify: I can fully understand why a person near a black hole thinks his friends in open space appear to have faster clocks. After all, the light he sees coming from them has been blueshifted. To use specific numbers, suppose they thought the light had a frequency of 2*10^15 Hz, and he thinks it has a frequency of 4*10^15 Hz. Frequency is cycles per second, so (dropping the 10^15 for clarity), an event which happens four times per our near-black-hole observer's second happens two times per our open-space observers' second. Thus, we see that the open-space observer's clock is twice as fast as the near-black-hole observer's clock. Anyway, the point is I get the basic concept of time running at different speeds because of gravity wells.

The only problem I have is with the center of the earth. In particular, I believe (or at least, feel intuitively) that since the middle of the earth feels no gravity, it should be equivalent to open space, and should have a clock that runs at the same rate as an open-space clock. Let's imagine that our center-of-earth observer has a long tube which goes to the surface and beyond, until there's no more effect of earth's gravity (which would take forever, but you get the idea). At the other end is a second observer. Can these two observers figure out which one is in the center of the earth and which one is in open space? If not, then how can the person in the center of the earth have a slower clock than the person on earth's surface, who would feel a gravity well (just like the person near the black hole)? Shouldn't the person in the center of the earth have a faster clock? This is the question I don't understand.

Henry J · 8 April 2005

Re "Shouldn't the person in the center of the earth have a faster clock? This is the question I don't understand."
I don't understand the mechanism behind the effect, either, but I think it would cause inconsistencies if clocks started going faster as one went deeper under the surface.

It's not just time that's warped, either - distance is contracted; the distance from surface to center is a bit more than would be expected if space obeyed Euclid.

One thought I'm having on the matter, is maybe descending into a gravity well reduces the rest mass of matter particles, and maybe the energy that's no longer tied up in mass form might be what goes into the kinetic energy as the falling object speeds up? If the particles in the lower altitude object have less mass energy, then an incoming photon would have more energy relative to the mass energy of those particles. I wonder if that thought is consistent with the math?

Henry

Marek14 · 9 April 2005

I wonder - how about the common (i.e. non-gravity) blue shift? If I travel directly to some place at fast speed, wouldn't the same logic tell me that time is speeding there (while, according to STR, you can't see any moving object experiencing faster time than yourself). As far as I understand it, the effects of light shift can be accounted for in STR, leaving clean time dilation as a result, but I would appreciate some thoughts on that.

Boronx · 9 April 2005

The only problem I have is with the center of the earth. In particular, I believe (or at least, feel intuitively) that since the middle of the earth feels no gravity, it should be equivalent to open space, and should have a clock that runs at the same rate as an open-space clock.

I remember from my basic physics class that under Genral Relativity, a clock at the top of an accelerating rocket ship runs *faster* than a clock at the bottom, even though both clocks are accelerating at the same speed.

The way I like to think of it is that light forces time to slow down in order to turn what ought to be a speed increase of falling photons into a blue shift.

Boronx · 9 April 2005

Marek, I am not a physicist, but here goes. First of all, I'd say that the effects of red shift due to time dilation and blue shift due to length contraction will cancel each other out.

Second, if you think about it, as you observe an object you're moving towards, you observe their time running faster, hence a blue shift, and you observe time runnng slower in objects that are moving away from you, hence the red shift.

let's say you're moving between two planets at half the speed of light. Normal time dilation effects for oberving both planets are the same: they both appear to be about 80 something percent of normal speed.

Except they don't. The planets are half a light year apart, and at the end of the years travel time, you've ovserved 2*80% years on planet two, but only 0.5*80% years on planet 1. So, you see double the frequency from planet two, but you also see their clocks running twice as fast. You see half the frequency from planet 1, but you also see their clocks running at half speed.

Randall Wald · 9 April 2005

Thanks for the example, Boronx. Now that I think about it, I remember the accelerating spaceship example from an excerpt of a Feynman lecture I once read. That shows my naive "acceleration directly relates to clock speed" idea can't be all right, and is probably mostly wrong. I probably should think more carefully about what exactly happens to light traveling between the surface and the center of the earth, and then figure out what that implies about clock speed.

Boronx · 9 April 2005

Well, that doesn't make sense. Let's say your spaceship leaves planet 1 at year 1. At that moment it's seeing light from planet 2 from year 0.5. When you reach planet2 at year 2, you're seeing light from planet 1 from year 1.5. That says to me that you've observed 1.5 years of planet 2 in your 1 year of travel, not 2. And I guess, if I think about the doppler effect, blue shift at 0.5c would be 50% increase in frequency, not 100%.

Boronx · 9 April 2005

I made a mistake. Let's say your spaceship leaves planet 1 at year 1. At that moment it's seeing light from planet 2 from year 0.5. When you reach planet2 at year 2, you're seeing light from planet 1 from year 1.5. That says to me that you've observed 1.5 years of planet 2 in your 1 year of travel, not 2. And I guess, if I think about the doppler effect, blue shift at 0.5c would be 50% increase in frequency, not 100%.

Koly · 9 April 2005

Randall, Henry,

you don't seem to like my analogy with kicking the ball out of the hole. But that's really what's going on, exactly the same thing happens to photon wavelengths as to ordinary matter. It's all only about loosing or gaining energy and momentum.

Imagine this - would a ball thrown out of the center of the Earth slow down or accelarate? Why do you then cannot accept that a light looses some energy too (=red shift)?

Noturus · 10 April 2005

The only problem I have is with the center of the earth. In particular, I believe (or at least, feel intuitively) that since the middle of the earth feels no gravity, it should be equivalent to open space, and should have a clock that runs at the same rate as an open-space clock.

— Randall Wald
I am not a physicist but what exactly is it about the center of the earth that causes it to not feel gravitational acceleration? Isn't that like saying that a black hole feels no acceleration? It just seems like unless an oberver was infinitely small it would still feel gravitational acceleration. Could be wrong of course. Thanks

Noturus · 10 April 2005

The only problem I have is with the center of the earth. In particular, I believe (or at least, feel intuitively) that since the middle of the earth feels no gravity, it should be equivalent to open space, and should have a clock that runs at the same rate as an open-space clock.

— Randall Wald
I am not a physicist, but why do you say that the middle of the earth feels no gravity? Doesn't it feel gravitational acceleration the same as any other point? The exact center may feel it in all directions at once, resulting in no movement, but that is not the same, is it? Could be wrong of course. Thanks

Noturus · 10 April 2005

Doh! So sorry about that Double now Triple Post! Feel free to delet either! And this one too.

steve · 10 April 2005

I am not a physicist, but why do you say that the middle of the earth feels no gravity? Doesn't it feel gravitational acceleration the same as any other point? The exact center may feel it in all directions at once, resulting in no movement, but that is not the same, is it?

Your problem here is the word 'feeling'. At the center, you wouldn't feel any gravitational pull, and there also would be no force on you. Force and feeling are related in tricky ways. Standing on earth's surface you feel gravity, but don't move. No net force. Free-falling toward earth's center, you would not feel gravity, but you would accelerate. Net force. Loitering in the exact center, you would not feel gravity, and would not move. No net force.

steve · 10 April 2005

Now if you really want a messed-up brain, consider the following true statement:

If the earth contained a hollow cavity in the center, you could float around, feeling no force, anywhere in the cavity, not just the very center.

I do not suggest getting stuck on that idea, it's not possible to understand without spending some time understanding things like Gauss's Law, and other tedium.

Henry J · 11 April 2005

Re "If the earth contained a hollow cavity in the center, you could float around, feeling no force, anywhere in the cavity, not just the very center."

Depends on the size of the cavity. At a mile from the center, for example, there'd be somewhere around 1/4000 of a G force toward the center. Not much, but not zero.

Henry

Henry J · 11 April 2005

Oops, cancel my last post. I just remembered that with a hollow spherical cavity centered at the center, well, it's the part "under" one that generates the net gravity. The 1/4000 is approximately what one would feel if in a tiny (hopefully air conditioned) cavity offset from the center by a mile.

Henry

Henry J · 11 April 2005

Oops, cancel my last post. I just remembered that with a hollow spherical cavity centered at the center, well, it's the part "under" one that generates the net gravity. The 1/4000 is approximately what one would feel if in a tiny (hopefully air conditioned) cavity offset from the center by a mile.

Henry

Henry J · 11 April 2005

Oh great, now cancel one of the two cancellations of the aforementioned post... Good grief.

fh · 11 April 2005

I do not suggest getting stuck on that idea, it's not possible to understand without spending some time understanding things like Gauss's Law, and other tedium.

— Steve
Let's try this without Gauss's Law, but perhaps a bit of tedium. For pics, see a standard 1st year calculus based physics text. Claim: At any point inside a hollow thin shell, the force from opposing differential(i.e. small) solid angles cancels. Proof: Case 1. If you are at the center it's obvious. Case 2. If the point under consideration is off center, the only possible direction of force is along the radius*. Now, because the lesser mass from the closer solid angle element is less proportionally by r_close^2 whereas the greater mass from the farther solid angle is greater proportionally by r_far^2. Since the force is proportional to 1/r^2, the force from these opposing solid angles exactly cancels. Finally, since a hollow sphere can be thought of as layered thin shells, there is no force from any shell of which the sphere is made. Hence no force inside the hollow sphere. The hole has to be spherical and concentric with the rest of the sphere. Each shell has to be of uniform density, but the density of each shell can vary with radius. * Landau would say this is obvious from the symmetry of the problem, and it is if you consider the mirror image of the proposed off radius force about a equatorial plane through the point in question.

fh · 11 April 2005

Please edit my non-sentence in the post above by joining the paragraphs beginning "Case 2. If the ...." and "Since the force ...." to read:

... by r_far^2, and since the force is ...

Thanks.

FH